Câu 1:
Ta có:
\(\begin{array}{l}
x = 10 - 3t + 0,2{t^2} \Rightarrow \left\{ \begin{array}{l}
{x_0} = 10m\\
{v_0} = - 3\left( {m/s} \right)\\
a = 0,4\left( {m/{s^2}} \right)
\end{array} \right.\\
v = {v_0} + at = - 3 + 0,4t
\end{array}\)
Câu 2:
\(v = - 2 + 3t \Rightarrow a = 3\left( {m/{s^2}} \right)\)
Câu 3:
\(a = \dfrac{{ - v_0^2}}{{2s}} = \dfrac{{ - {{10}^2}}}{{2.10}} = - 5\left( {m/{s^2}} \right)\)
