$\text{Đáp án + Giải thích các bước giải:}$
`1//3x-12=0`
`<=>3x=12`
`<=>x=4`
`\text{Vậy}` `S={4}`
`2//(x-2)(2x+3)=0`
`<=>` \(\left[ \begin{array}{l}x-2=0\\2x+3=0\end{array} \right.\)
`<=>` \(\left[ \begin{array}{l}x=2\\2x=-3\end{array} \right.\)
`<=>` \(\left[ \begin{array}{l}x=2\\x=-\dfrac{3}{2}\end{array} \right.\)
`\text{Vậy}` `S={2;-(3)/(2)}`
`3//(x+2)/(x-2)-(6)/(x+2)=(x^{2})/(x^{2}-4)` `(ĐKXĐ:x\ne±2)`
`<=>((x+2)^{2})/((x-2)(x+2))-(6(x-2))/((x+2)(x-2))=(x^{2})/((x-2)(x+2))`
`=>(x+2)^{2}-6(x-2)=x^{2}`
`<=>x^{2}+4x+4-6x+12-x^{2}=0`
`<=>-2x+16=0`
`<=>-2x=-16`
`<=>x=8(TM)`
`\text{Vậy}` `S={8}`
