Em tham khảo nha:
\(\begin{array}{l}
1)\\
C{H_3} - CH = C(C{H_3}) - C{H_3}\\
2)\\
nhh = \dfrac{{3,36}}{{22,4}} = 0,15mol\\
Mhh = \dfrac{{7,7}}{{0,15}} = 51,33g/mol\\
\Rightarrow 14n = 51,33 \Rightarrow n = 3,67\\
\Rightarrow CTPT:{C_3}{H_6},{C_4}{H_8}
\end{array}\)