Đáp án:
\(a.\ n_{KNO_3}=1\ \text{mol}, m_{KNO_3}=101\ \text{gam}\\ b. \ n_{CaCl_2}=0,025\ \text{mol},m_{CaCl_2}=2,775\ \text{gam}\)
Giải thích các bước giải:
\(a.\ n_{KNO_3}=C_M.V=2.0,5=1\ \text{mol}\\\to m_{KNO_3}=1.101=101\ \text{gam}\\ b.\ n_{CaCl_2}=0,1.0,25=0,025\ \text{mol}\\\to m_{CaCl_2}=0,025.111=2,775\ \text{gam}\)