Đáp án:
C
Giải thích các bước giải:
\(\begin{array}{l}
{C_2}{H_5}OH + {O_2} \xrightarrow{ lên men} C{H_3}COOH + {H_2}O(1)\\
C{H_3}COOH + {C_2}{H_5}OH \xrightarrow{xt} C{H_3}COO{C_2}{H_5} + {H_2}O(2)\\
n{C_2}{H_5}OH(2) = nC{H_3}COOH(2) = nC{H_3}COO{C_2}{H_5} = 1\,mol\\
H = 62,5\% \Rightarrow n{C_2}{H_5}OH(2) = nC{H_3}COOH(2) = \dfrac{1}{{62,5\% }} = 1,6\,mol\\
n{C_2}{H_5}OH(1) = nC{H_3}COOH(1) = 1,6\,mol\\
H = 80\% \Rightarrow n{C_2}{H_5}OH(1) = \dfrac{{1,6}}{{80\% }} = 2\,mol\\
n{C_2}{H_5}OH = 2 + 1,6 = 3,6\,mol\\
m{C_2}{H_5}OH = 3,6 \times 46 = 165,6g
\end{array}\)