Em tham khảo nha:
\(\begin{array}{l}
a)\\
{p_{{}_{29}^{63}Cu}} = {p_{{}_{29}^{65}Cu}} = 29\\
{n_{{}_{29}^{63}Cu}} = 63 - 29 = 34\\
{n_{{}_{29}^{65}Cu}} = 65 - 29 = 36\\
b)\\
hh:{}_{29}^{63}Cu(a\,\% ),{}_{29}^{65}Cu(b\,\% )\\
\left\{ \begin{array}{l}
a + b = 1\\
63a + 65b = 63,54
\end{array} \right.\\
\Rightarrow a = 73\% ;b = 27\%
\end{array}\)