Lời giải:
$A)$ `2/3 x.(x -4) = 0`
$⇔ \left[ \begin{array}{l}\dfrac{2x}{3}=0\\x -4=0\end{array} \right. ⇔ \left[ \begin{array}{l}x=0\\x=4\end{array} \right.$
Vậy `S = {0; 4}`
---------------
$B)$ `(x +2)² -(x -2).(x +2) = 0`
`⇔ (x +2).(x +2 -x +2) = 0`
`⇔ (x +2).4 = 0`
`⇔ x +2 = 0`
`⇔ x = -2`
Vậy `S = {-2}`