Đáp án:
\(\begin{array}{l}
21.\\
{F_h} = 12500N\\
22.\\
a.\\
a = 3,268m/{s^2}\\
t = 2s\\
b.\\
s = 6,737m
\end{array}\)
Giải thích các bước giải:
\(\begin{array}{l}
21.\\
a = \frac{{{v^2} - {v_0}^2}}{{2l}} = \frac{{ - {{10}^2}}}{{2.20}} = - 2,5m/{s^2}\\
- {F_h} = ma\\
{F_h} = - ma = - 5000. - 2,5 = 12500N\\
22.\\
a.\\
{{\vec F}_{ms}} + \vec N + \vec P = m\vec a\\
N = P\cos 30\\
P\sin 30 - {F_{ms}} = ma\\
a = \frac{{P\sin 30 - {F_{ms}}}}{m} = \frac{{mg\sin 30 - \mu mg\cos 30}}{m} = 10\sin 30 - 0,2.10.\cos 30 = 3,268m/{s^2}\\
s = \frac{1}{2}a{t^2}\\
t = \sqrt {\frac{{2s}}{a}} = \sqrt {\frac{{2.6,54}}{{3,268}}} = 2s\\
b.\\
{{\vec F}_{ms}} + \vec N + \vec P = m\vec a'\\
- {F_{ms}} = ma'\\
a' = \frac{{ - {F_{ms}}}}{m} = - \mu 'g = - 0,3.10 = - 3m/{s^2}\\
a = \frac{{{v^2} - {v_0}^2}}{{2l}}\\
3,268 = \frac{{{v^2}}}{{2.6,54}}\\
v = 6,538m/s\\
s = \frac{{v{'^2} - {v^2}}}{{2a'}} = \frac{{ - 6,{{538}^2}}}{{2. - 3}} = 6,737m
\end{array}\)