3)
\(FeCl_3\): muối: sắt (III) clorua
\(Mg(OH)_2\): bazo: magie hidroxit
\(Ag_2O\): oxit bazo: bạc oxit
\(H_2SO_4\): axit: axit sunfuric
4)
a)
Ta có:
\({n_{CuS{O_4}}} = \frac{{16}}{{64 + 32 + 16.4}} = 0,1{\text{ mol}}\)
\({V_{dd}} = 200{\text{ ml = 0}}{\text{,2 lít}}\)
\( \to {C_{M{\text{ CuS}}{{\text{O}}_4}}} = \frac{{0,1}}{{0,2}} = 0,5M\)
b)
Ta có:
\({m_{{H_2}S{O_4}}} = 150.9,8\% = 14,7{\text{ gam}}\)
\( \to {n_{{H_2}S{O_4}}} = \frac{{14,7}}{{1.2 + 32 + 16.4}} = 0,15{\text{ mol}}\)
5)
Phản ứng xảy ra:
\(Zn + 2HCl\xrightarrow{{}}ZnC{l_2} + {H_2}\)
Ta có:
\({n_{Zn}} = \frac{{13}}{{65}} = 0,2{\text{ mol = }}{{\text{n}}_{ZnC{l_2}}}\)
\( \to {m_{ZnC{l_2}}} = 0,2.(65 + 35,5.2) = 27,2{\text{ gam}}\)
\({n_{HCl}} = 2{n_{Zn}} = 0,2.2 = 0,4{\text{ mol}}\)
\( \to {m_{HCl}} = 0,4.36,5 = 14,6{\text{ gam}}\)
\( \to C{\% _{HCl}} = \frac{{{m_{HCl}}}}{{{m_{dd}}}} = \frac{{14,6}}{{182,5}} = 8\% \)