$\\$
Qua `B` kẻ $Bh//Ax$ (`Bh` nằm giữa `BA` và `BC`)
`->hat{xAB}=hat{ABh}` (2 góc so le trong)
Có : $Bh//Ax, Ax//Cy$
$→ Bh//Cy$
`->hat{yCB}=hat{CBh}` (2 góc so le trong)
Có : `hat{ABC}=hat{ABh}+hat{CBh}=hat{xAB}+hat{yCB}`
`->hat{ABC}=hat{xAB}=hat{yCB}` (Đpcm)