Đáp án:
\({m_{Zn}} = 6,5{\text{ gam}}; {{\text{m}}_{ZnO}} = 4,05{\text{ gam}}\)
\( {m_{dd{\text{ HCl}}}} = 109,5{\text{ gam}}\)
Giải thích các bước giải:
Phản ứng xảy ra:
\(Zn + 2HCl\xrightarrow{{}}ZnC{l_2} + {H_2}\)
\(ZnO + 2HCl\xrightarrow{{}}ZnC{l_2} + {H_2}O\)
Ta có:
\({n_{{H_2}}} = \frac{{2,24}}{{22,4}} = 0,1{\text{ mol = }}{{\text{n}}_{Zn}}\)
\( \to {m_{Zn}} = 0,1.65 = 6,5{\text{ gam}} \to {{\text{m}}_{ZnO}} = 10,55 - 6,5 = 4,05{\text{ gam}}\)
\( \to {n_{ZnO}} = \frac{{4,05}}{{65 + 16}} = 0,05{\text{ mol}}\)
\( \to {n_{HCl}} = 2{n_{Zn}} + 2{n_{ZnO}} = 0,3{\text{ mol}}\)
\( \to {m_{HCl}} = 0,3.36,5 = 10,95{\text{ gam}}\)
\( \to {m_{dd{\text{ HCl}}}} = \frac{{10,95}}{{10\% }} = 109,5{\text{ gam}}\)
