`Fe+2HCl->FeCl_2+H_2`
`Mg+2HCl->MgCl_2+H_2`
`a)``n_{Fe;Mg}=a;b`
`n_{H_2}=(6,72)/(22,4)=0,3(mol)=x+y`
`m_{hh}=56x+24y=13,6`
`x=0,2;y=0,1`
`%m_{Fe}=(0,2.56)/(13,6%)=82,35%`
`%m_{Mg}=100%-82,35%=17,65%`
`b)``mdd_{HCl}=([(0,2.2)+(0,1.2)].36,5)/(14,6%)=150(g)`
`n_{FeCl_2}=n_{Fe}=0,2(mol)`
`n_{MgCl_2}=n_{Mg}=0,1(mol)`
`%m_{FeCl_2}=(0,2.(56+35,5.2))/(13,6+ 150-0,3.2).100=15,59%`
`%m_{MgCl_2}=(0,1.(24+35,5.2))/(13,6+150-0,3.2).100=5,82%`