Đáp án:
b)(x-2)(x-1)=x-2
⇔(x-2)(x-1)-(x-2)=0
⇔(x-2)(x-1-1)=0
⇔(x-2)(x-2)=0
⇔x-2=0
⇔x=2
Vậy x=2
c)4-(x+1)/3=(5-2x)/5
⇔60-5x-5=15-6x
⇔x=40
Vây x=40
d)5/(2x^2-3x)=3/(4x-6)-(4+3x)/((2x-3)^2) ĐKXĐ:x khác 3/2;0
⇔5/(x*(2x-3))=3/(2*(2x-3))-(4+3x)/((2x-3)^2)
⇔20x-30=6x^2-9x-8x-6x^2
⇔3x=30
⇔ x=10(n)
Vậy x=10
