$\\$
`a,`
`3/(2x) = (2x)/3 (x \ne 0)`
`-> 3 . 3 = 2x . 2x`
`-> 4x^2 = 9`
`-> x^2=9 : 4`
`->x^2=9/4`
`->` \(\left[ \begin{array}{l}x^2=(\dfrac{3}{2})^2\\x^2=(\dfrac{-3}{2})^2\end{array} \right.\) $\\$ `->` \(\left[ \begin{array}{l}x=\dfrac{3}{2}\\x=\dfrac{-3}{2}\end{array} \right.\) (Thỏa mãn)
Vậy `x=3/2` hoặc `x=(-3)/2`
$\\$
`b,`
`2/(x+1) = 5/(3x-2) (x \ne -1, x\ne 2/3)`
`-> 2 . (3x-2) = 5 . (x+1)`
`-> 6x - 4 = 5x + 5`
`-> 6x-5x=4+5`
`-> x=9` (Thỏa mãn)
Vậy `x=9`
