Đặt :
mMg mp = x mol
nAl mp = y mol
P1 :
nH2SO4 = 0.04 mol
Mg + H2SO4 => MgSO4 + H2
x_______x
2Al + 3H2SO4 => Al2(SO4)3 + 3H2
y________1.5y
<=> x + 1.5y = 0.04 (1)
P2:
nSO2 = 0.01 mol
Mg => SO2
0.01_____0.01
nAl = (0.04-0.01)/1.5 * 2 = 0.04 mol
nMg = 0.02 mol
mKL = 0.04*27 + 0.02*24 = 1.56 g
nH2 = nH2SO4 = 0.04 mol
VH2 = 0.896 (l)