`n_(CO_2)=\frac{1,68}{22,4}=0,075(mol)`
`CO_2+2KOH->K_2CO_3+H_2O`
`0,075` `0,075`
`=>C_(MK_2CO_3)=\frac{0,075}{0,25}=0,3M`
Đổi $250ml=0,25l$
$2KOH+CO_2→K_2CO_3+H_20$
$nCO_2=1,68/22,4=0,075(mol)$
$⇒nK_2CO_3=0,075(mol)$
$⇒mK_2CO_3=0,075/0,25=0,3M$
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giải pt : $\frac{3}{\sqrt{3x-8}+1}$ - $\frac{1}{\sqrt{x+1}+2}$= $\frac{2}{5}$
Help me please. Thank you very much
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