Đáp án:
$a/$
C2H5OH + Na --> C2H5ONa + 1/2H2
x x x 1/2x
C6H5OH + Na -to-> C6H5ONa + 1/2H2
y y y 1/2y
$b/$
$nH2 = 0,252/22,4 = 0,01125 (mol)$
Ta có:
$\left \{ {{46x + 94y = 1,755} \atop {1/2x + 1/2y = 0,01125}} => \right.$ $\left \{ {{x=0,0075} \atop {x=0,015}} \right.$
%$mC2H5OH = $$\frac{0,0075.46}{1,755}$$.100 = 19,66$%
%$mC6H5OH = 100 - 19,66 = 80,34$%
$c/$
$m = mC2H5ONa + mC6H5ONa$
$= 0,0075.68 + 0,015.116 = 2,25 (g)$