Hỗn hợp `X` gồm $\begin{cases}C_2H_6:x(mol)\\C_2H_4:y(mol)\\C_2H_2:z(mol)\\\end{cases}$
`a,`
`CH_2=CH_2+Br_2->CH_2Br-CH_2Br`
`CH\equivCH+2Br_2->CHBr_2\equivCHBr_2`
$CH\equiv CH+Ag_2O\xrightarrow{dd NH_3}CAg\equiv CAg+H_2O$
`b,`
Ta có
`\sumn_{\pi}=y+2z(mol)`
Bảo toàn `\pi`
`y+2z=n_{Br_2}`
`=>y+2z=0,1.0,6=0,06(mol)`
Lại có
`n_{C_2H_2}=n_{Ag_2C_2}=z`
`=>z=\frac{3,6}{240}=0,015(mol)`
`=>y=0,03(mol)`
`=>%m_{C_2H_4}=\frac{0,03.28}{1,83}.100=45,9%`
`%m_{C_2H_2}=\frac{0,015.26}{1,83}.100=21,31%`
`=>%m_{C_2H_6}=100-45,9-21,31=32,79%`