`nKOH = 0,1 (mol)`
`2KOH + ZnSO4 → Zn(OH)2↓ + K2SO4`
`a, nZn(OH)2 = 1/2 .nKOH=0,05 (mol)`
` mZn(OH)2 = 0,05.99=4,95 (g)`
`b, nZnSO4 = 1/2 .nKOH = 0,05 (mol)`
` => VZnSO4 =0,05:2=0,025 (l)`
`c, V dd` mới `=0,025 + 0,1=0,125 (l)`
`nK2SO4 = 1/2 .nKOH =0,05 (mol)`
` => CM K2SO4 =0,05:0,125=0,4 (M)`