$10a^2=10b^2-c^2$
$\Leftrightarrow 40a^2=40b^2-4c^2$
$\Leftrightarrow 4c^2=40b^2-40a^2$
$(7a-3b-2c)(7a-3b+2c)$
$=[(7a-3b)-2c].[(7a-3b)+2c]$
$=(7a-3b)^2-(2c)^2$
$=(7a-3b)^2-4c^2$
$=(7a-3b)^2+40a^2-40b^2$
$=49a^2-42ab+9b^2+40a^2-40b^2$
$=89a^2-42ab-31b^2$
Mà $(3a-7b)^2=9a^2-42ab+49b^2$
Vậy không thể CM.