$n_{H_2}=8,96/22,4=0,4mol$
$PTHH :$
$2Al+3H_2SO_4\to Al_2(SO_4)_3+3H_2↑$
$ Zn+H_2SO_4\to ZnSO_4+H_2$
a/Gọi $n_{Al}=a;n_{Zn}=b$
Ta có :
$m_{hh}=27a+65b=11,9$
$n_{H_2}=1,5a+b=0,4$
Ta có hpt :
$\left\{\begin{matrix}
27a+65b=11,9 & \\
1,5a+b=0,4 &
\end{matrix}\right.$
$⇔\left\{\begin{matrix}
a=0,2 & \\
b=0,1 &
\end{matrix}\right.$
$⇒m_{Al}=0,2.27=5,4g$
$m_{Zn}=11,9-5,4=6,5g$
$c/2Al+6H_2SO_4\to Al_2(SO_4)_3+6H_2O+3SO_2$
$ Zn+H_2SO_4\to 2H_2O+SO_2+ZnSO_4$
$n_{SO_2}=1,5a+b=1,5.0,2+0,1=0,4mol$
$⇒V_{SO_2}=0,4.22,4=8,96l$