Đáp án:
58,18% và 41,82%
Giải thích các bước giải:
\(\begin{array}{l}
CTTQ\,:{C_{\overline n }}{H_{2\overline n + 1}}OH(\overline n > 1)\\
2{C_{\overline n }}{H_{2\overline n + 1}}OH + 2Na \to 2{C_{\overline n }}{H_{2\overline n + 1}}ONa + {H_2}\\
{n_{{H_2}}} = \dfrac{{3,36}}{{22,4}} = 0,15\,mol\\
{n_{{C_{\overline n }}{H_{2\overline n + 1}}OH}} = 2{n_{{H_2}}} = 0,3\,mol\\
{M_{hh}} = \dfrac{{11}}{{0,3}} = 36,67g/mol\\
\Rightarrow 14\overline n + 18 = 36,67 \Rightarrow \overline n = 1,33\\
CTPT:C{H_3}OH,{C_2}{H_5}OH\\
hh:C{H_3}OH(a\,mol),{C_2}{H_5}OH(b\,mol)\\
\left\{ \begin{array}{l}
a + b = 0,3\\
32a + 46b = 11
\end{array} \right.\\
\Rightarrow a = 0,2;b = 0,1\\
\% {m_{C{H_3}OH}} = \dfrac{{0,2 \times 32}}{{11}} \times 100\% = 58,18\% \\
\% {m_{{C_2}{H_5}OH}} = 100 - 58,18 = 41,82\%
\end{array}\)
