n khí=$\frac{33,6}{22,4}$=1,5(mol)
PTHH: Cu+H2SO4→ko xảy ra
Zn+H2SO4→ZnSO4+H2
1,5 1,5
a) Theo pt=>nZn=nH2=1,5(mol)
=>mZn=1,5.65=97,5 (g)>mhh (vô lí)
sửa đề: Vkhí=3,36 (l)
=>n khí=0,15(mol)
theo pthh=>nZn=0,15(mol)
=>mZn=0,15.65=9,75(g)
=>mCu=15,75-9,75=6(g)
b) Theo pt=>nZnSO4=nZn=0,15(mol)
=>mZnSO4=0,15.161=24,15(g)