Đáp án:
\(\begin{array}{l} b,\ C\%_{KCl}=14,8\%\\ c,\ V_{SO_2}=2,24\ lít.\end{array}\)
Giải thích các bước giải:
\(\begin{array}{l} a,\\ PTHH:K_2SO_3+2HCl\to 2KCl+SO_2↑+H_2O\\ b,\\ n_{K_2SO_3}=\dfrac{15,8}{158}=0,1\ mol.\\ Theo\ pt:\ n_{HCl}=2n_{K_2SO_3}=0,2\ mol.\\ \Rightarrow m_{\text{dd HCl}}=\dfrac{0,2\times 36,5}{8\%}=91,25\ g.\\ Theo\ pt:\ n_{SO_2}+n_{K_2SO_3}=0,1\ mol.\\ \Rightarrow m_{\text{dd spư}}=m_{K_2SO_3}+m_{\text{dd HCl}}-m_{SO_2}\\ \Rightarrow m_{\text{dd spư}}=15,8+91,25-0,1\times 64=100,65\ g.\\ Theo\ pt:\ n_{KCl}=2n_{K_2SO_3}=0,2\ mol.\\ \Rightarrow C\%_{KCl}=\dfrac{0,2\times 74,5}{100,65}\times 100\%=14,8\%\\ c,\\ V_{SO_2}=0,1\times 22,4=2,24\ lít.\end{array}\)
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