Đáp án:
\({V_{dd{\text{ }}{\text{HCl}}}}= 37,5{\text{ ml}}\)
Giải thích các bước giải:
Phản ứng xảy ra:
\(HCl + AgN{O_3}\xrightarrow{{}}AgCl + HN{O_3}\)
\(NaCl + AgN{O_3}\xrightarrow{{}}AgCl + NaN{O_3}\)
Ta có:
\({n_{AgN{O_3}}} = \frac{{51}}{{108 + 62}} = 0,3{\text{ mol}}\)
\({m_{dd{\text{ HCl}}}} = 16,59.1,1 = 18,249{\text{ gam}}\)
\( \to {m_{HCl}} = 18,249.20\% = 3,65{\text{ gam}}\)
\( \to {n_{HCl}} = \frac{{3,65}}{{36,5}} = 0,1{\text{ mol}}\)
\( \to {n_{NaCl}} = {n_{AgN{O_3}}} - {n_{HCl}} = 0,3 - 0,1 = 0,2{\text{ mol}}\)
\( \to {m_{NaCl}} = 0,2.(23 + 35,5) = 11,7{\text{ gam}}\)
\( \to {m_{dd\;{\text{HCl}}}} = \frac{{11,7}}{{26\% }} = 45{\text{ gam}}\)
\( \to {V_{dd{\text{ }}{\text{HCl}}}} = \frac{{45}}{{1,2}} = 37,5{\text{ ml}}\)
