Ta có : {nFeO=nFe2O3
72.nFeO=160.nFe2O3=17,44
⇒nFeO=nFe2O3=0,075(mol)⇒nFeO=nFe2O3=0,075(mol)
PTHH: FeO+2HCl-->FeCl2+H2O
...........0,075.....0,15.....0,075.............(mol)
Fe2O3+6HCl-->2FeCl3+3H2O
0,075......0,45................................(mol)
a, CM FeCl2=0,075/0,45=0,17(M)
CM FeCl3=0,15/0,45=0,33(M)
b, FeCl2+2NaOH-->Fe(OH)2+2NaCl
FeCl3+3NaOH-->Fe(OH)3+3NaCl
⇒nNaOH=0,15+0,45=0,6(mol)⇒nNaOH=0,15+0,45=0,6(mol)
⇒VNaOH=0,62,5=0,24l