a) nCu= 2,3/64= 23/640 (mol)
$Cu^{0}$ $\to$ $Cu^{+2}$ $+$ $2e$
$\frac{23}{640}$.....................$\frac{46}{640}$ $(mol)$
$S^{+6}$ $+$ $2e$ $\to$ $S^{+4}$
x............2x
Bảo toàn e: 2x = 46/640
=> x= 23/640 (mol)
=> VSO2= (23/640).22,4= 0,805 (l)
b) Bảo toàn nguyên tố Cu:
nCu (trong muối) = nCu= 23/640 (mol)
=> mCuSO4= (23/640).160= 5,75 (g)