a,
$n_{Na}=\dfrac{2,3}{23}=0,1(mol)$
$2Na+2HCl\to 2NaCl+H_2$
$\Rightarrow n_{H_2}=\dfrac{n_{Na}}{2}=0,05(mol)$
$\to V_2=V_{H_2}=0,05.22,4=1,12l$
b,
$n_{HCl}=n_{Na}=0,1(mol)$
$V_{dd HCl}=\dfrac{0,1}{1}=0,1l=100ml$
$\to V_1=100ml$
c,
$n_{NaCl}=n_{Na}=0,1(mol)$
$AgNO_3+NaCl\to AgCl+NaNO_3$
$\Rightarrow n_{AgCl\downarrow}=n_{NaCl}=0,1(mol)$
$\to a=0,1.143,5=14,35g$