Đáp án:
a) PTHH: 2Al+3H2SO4=Al2(SO4)3+3H2
theo PT: nH2SO4/nAl=3/2
=>nH2SO4=3/2.nAl=3/2.0,1=0,15(mol)
=>mH2SO4=n.M=0,15.98=14,7(g)
b)theo PT: nAl2(SO4)3/nAl=1/2
=>nAl2(SO4)3=1/2.nAl=1/2.0,1=0,05(mol)
=>mAl2(SO4)3=n.M=0,05.342=17,1(g)
c) theo PT nH2/nAl=3/2
=>nH2=3/2.nAl=3/2.0,1=0,15(mol)
=>VH2=nH2x22,4=0,15.22,4=3,36(l)
from to phùng mạnh dũng 28/12/2007