Sửa đề: $Cu$ và $CuO$
a,
$n_{SO_2}=\dfrac{4,48}{22,4}=0,2(mol)$
Bảo toàn e: $2n_{Cu}=2n_{SO_2}$
$\to n_{Cu}=0,2(mol)$
$\to m_{Cu}=0,2.64=12,8g$
$\%m_{Cu}=\dfrac{12,8.100}{20,8}=61,54\%$
$\to \%m_{CuO}=100-61,54=38,46\%$
b,
$n_{CuO}=\dfrac{20,8-12,8}{80}=0,1(mol)$
Bảo toàn $Cu$: $n_{CuSO_4}=n_{Cu}+n_{CuO}=0,3(mol)$
$\to m_{CuSO_4}=0,3.160=48g$
Bảo toàn $S$:
$n_{H_2SO_4}=n_{CuSO_4}+n_{SO_2}=0,5(mol)$
$\to m_{dd H_2SO_4}=0,5.98:80\%=61,25g$