a, Mg+ 2HCl -> MgCl2+ H2
b,
nH2= nMg= 6,72/22,4= 0,3 mol
=> mMg= 0,3.24= 7,2g
%Mg= 7,2.100/20= 36%
%Ag= 100-36= 64%
c,
nHCl= 0,3.2= 0,6 mol
C% HCl= 0,6.36,5.100:150= 14,6%
d,
nMgCl2= 0,3 mol
m dd spu= 7,2+ 150- 0,3.2= 156,6g
C% MgCl2= 0,3.95.100:156,6= 18,2%