Đáp án:
\( \% {m_{Zn}} = 30,95\% \)
\( \% {m_{ZnO}} = 69,05\% \)
Giải thích các bước giải:
Phản ứng xảy ra:
\(Zn + {H_2}S{O_4}\xrightarrow{{}}ZnS{O_4} + {H_2}\)
Ta có:
\({n_{{H_2}}} = \frac{{2,24}}{{22,4}} = 0,1{\text{ mol}}\)
\( \to {n_{Zn}} = {n_{{H_2}}} = \frac{{2,24}}{{22,4}} = 0,1{\text{ mol}}\)
\( \to {m_{Zn}} = 0,1.65 = 6,5{\text{ gam}}\)
\( \to \% {m_{Zn}} = \frac{{6,5}}{{21}} = 30,95\% \)
\( \to \% {m_{ZnO}} = 100\% - 30,95\% = 69,05\% \)