Đáp án:
\(\begin{array}{l}
{m_{Cu}} = 25,6g\\
C{M_{FeS{O_4}}} = 1M\\
C{M_{CuS{O_4}(dư)}} = 0,4M
\end{array}\)
Giải thích các bước giải:
\(\begin{array}{l}
Fe + C{\rm{uS}}{O_4} \to FeS{O_4} + Cu\\
{n_{Fe}} = 0,4mol\\
{m_{{\rm{dd}}CuS{O_4}}} = 448g\\
\to {m_{CuS{O_4}}} = \dfrac{{448 \times 20\% }}{{100\% }} = 89,6g\\
\to {n_{CuS{O_4}}} = 0,56mol\\
\to {n_{Fe}} < {n_{CuS{O_4}}} \to {n_{CuS{O_4}}}dư
\end{array}\)
\(\begin{array}{l}
\to {n_{Cu}} = {n_{CuS{O_4}}} = {n_{FeS{O_4}}} = {n_{Fe}} = 0,4mol\\
\to {m_{Cu}} = 25,6g\\
\to {n_{CuS{O_4}(dư)}} = 0,16mol\\
\to C{M_{FeS{O_4}}} = \dfrac{{0,4}}{{0,4}} = 1M\\
\to C{M_{CuS{O_4}(dư)}} = \dfrac{{0,16}}{{0,4}} = 0,4M
\end{array}\)
