Đáp án:
\( {m_{Zn}} = 6,5{\text{ gam}}\)
\( {m_{ZnO}} = 16,2{\text{ gam}}\)
\( {V_{dd{\text{ HCl}}}} = 0,6{\text{ lít}}\)
Giải thích các bước giải:
Phản ứng xảy ra:
\(Zn + 2HCl\xrightarrow{{}}ZnC{l_2} + {H_2}\)
\(ZnO + 2HCl\xrightarrow{{}}ZnC{l_2} + {H_2}O\)
Ta có:
\({n_{{H_2}}} = \frac{{2,24}}{{22,4}} = 0,1{\text{ mol = }}{{\text{n}}_{Zn}}\)
\( \to {m_{Zn}} = 0,1.65 = 6,5{\text{ gam}}\)
\( \to {m_{ZnO}} = 22,7 - 6,5 = 16,2{\text{ gam}}\)
\({n_{ZnO}} = \frac{{16,2}}{{65 + 16}} = 0,2{\text{ mol}}\)
\( \to {n_{HCl}} = 2{n_{Zn}} + 2{n_{ZnO}} = 0,1.2 + 0,2.2 = 0,6{\text{ mol}}\)
\( \to {V_{dd{\text{ HCl}}}} = \frac{{0,6}}{1} = 0,6{\text{ lít}}\)
