Đáp án:
a, \({m_{Ba{{(HS)}_2}}} = 40,6g\)
b, \(C{M_{Ba{{(HS)}_2}}} = \dfrac{n}{V} = \dfrac{{0,2}}{{0,2}} = 1M\)
Giải thích các bước giải:
\(\begin{array}{l}
{n_{{H_2}S}} = \dfrac{{250 \times 6,8}}{{100 \times 34}} = 0,5mol\\
{n_{Ba{{(OH)}_2}}} = 0,2mol\\
\to \dfrac{{{n_{O{H^ - }}}}}{{{n_{{H_2}S}}}} = \dfrac{{0,2 \times 2}}{{0,5}} = 0,8
\end{array}\)
Tạo ra muối axit, \({H_2}S\) dư
\(\begin{array}{l}
2{H_2}S + Ba{(OH)_2} \to Ba{(HS)_2} + 2{H_2}O\\
{n_{Ba{{(HS)}_2}}} = {n_{Ba{{(OH)}_2}}} = 0,2mol\\
\to {m_{Ba{{(HS)}_2}}} = 40,6g\\
\to C{M_{Ba{{(HS)}_2}}} = \dfrac{n}{V} = \dfrac{{0,2}}{{0,2}} = 1M
\end{array}\)
