$n_{CO2}$ = 6,72/22,4 = 0,3 (mol)
a) Gọi x = $n_{MgCO3}$, y = $n_{Na2CO3}$
PT: MgCO3 + 2CH3COOH ---> (CH3COO)2Mg + H2O + CO2
PƯ: x 2x x x (mol)
PT: Na2CO3 + 2CH3COOH ---> 2CH3COONa + H2O + CO2
PƯ: y 2y 2y y (mol)
Ta có hệ phương trình:
$\left \{ {{84x+106y=27,4} \atop {x+y=0,3}} \right.$
=> $\left \{ {{x=0,2} \atop {y=0,1}} \right.$ (mol)
b) $V_{CH3COOH}$ = n/CM = (2.0,2+2.0,1)/2 = 0,3 (l)
c) $CM_{(CH3COO)2Mg}$ = n/V = 0,2/0,3 = 2/3 (M)
$CM_{CH3COONa}$ = n/V = 2.0,1/0,3 = 2/3 (M)
d)
PT: CH3COOH + NaOH ---> CH3COONa + H2O
PƯ: (2.0,2+2.01) 0,6 (mol)
$CM_{NaOH}$ = n/V = 0,6/0,1 = 6 (M)
Xin câu trả lời hay nhất ạ :3