Đáp án đúng: A
Giải chi tiết:Glucozơ và fructozơ có cùng CTPT C6H12O6, đều tham gia phản ứng tráng bạc với tỉ lệ nGlu/Fruc : nAg =1:2. \(\begin{array}{l}\left\{ \begin{array}{l}1\,CH \equiv C - CHO{\rm{ }} \to 1\,AgC \equiv C - COON{H_4} \downarrow + 2Ag \downarrow \\\,\,\,\,\,\,\,\,x\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, \to \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,x\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,2x{\rm{ }}\\1{C_6}{H_{12}}{O_6}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, \to 2Ag \downarrow \\\,\,\,\,\,\,\,\,y\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, \to \,\,\,\,2y{\rm{ }}\end{array} \right.\\ \Rightarrow \left\{ \begin{array}{l}54x + 180y = 28,8\\194x + 108.(2x + 2y) = 103,6\end{array} \right. \Rightarrow \left\{ \begin{array}{l}x = 0,2\\y = 0,1\end{array} \right.\\ \Rightarrow \% propinal{\rm{ (X) = }}\frac{{0,2.54}}{{28,8}}.100 = 37,5\% .\end{array}\)
Đáp án A
