Em tham khảo nha:
\(\begin{array}{l}
a)\\
Cu + 2{H_2}S{O_4} \to CuS{O_4} + S{O_2} + 2{H_2}O\\
CuO + {H_2}S{O_4} \to CuS{O_4} + {H_2}O\\
b)\\
{n_{S{O_2}}} = \dfrac{{5,6}}{{22,4}} = 0,25\,mol \Rightarrow {n_{Cu}} = {n_{S{O_2}}} = 0,25\,mol\\
\Rightarrow {n_{CuO}} = \dfrac{{28 - 0,25 \times 64}}{{80}} = 0,15\,mol\\
{n_{{H_2}S{O_4}}} = \dfrac{{112 \times 70\% }}{{98}} = 0,8\,mol\\
\Rightarrow {n_{{H_2}S{O_4}}} = 0,8 - 0,25 \times 2 - 0,15 = 0,15\,mol\\
{m_{{\rm{dd}}spu}} = 28 + 112 - 0,25 \times 64 = 124g\\
C{\% _{{H_2}S{O_4}}} = \dfrac{{0,15 \times 98}}{{124}} \times 100\% = 11,85\% \\
C{\% _{CuS{O_4}}} = \dfrac{{0,4 \times 160}}{{124}} \times 100\% = 51,61\% \\
c)\\
\% {m_{Cu}} = \dfrac{{0,25 \times 64}}{{28}} \times 100\% = 57,14\% \\
\% {m_{CuO}} = 100 - 57,14 = 42,86\%
\end{array}\)
