Đáp án:
Giải thích các bước giải:
$a,PTPƯ:$
$Zn+2HCl\xrightarrow{} ZnCl_2+H_2↑$ $(1)$
$CuO+H_2\xrightarrow{t^o} Cu+H_2O$ $(2)$
$b,n_{Zn}=\dfrac{3,5}{65}=\dfrac{7}{130}mol.$
$Theo$ $pt1:$ $n_{H_2}=n_{Zn}=\dfrac{7}{130}mol.$
$⇒V_{H_2}=\dfrac{7}{130}.22,4=1,2l.$
$c,Theo$ $pt2:$ $n_{Cu}=n_{H_2}=\dfrac{7}{130}mol.$
$⇒m_{Cu}=\dfrac{7}{130}.64=3,446g.$
$Theo$ $pt2:$ $n_{H_2O}=n_{H_2}=\dfrac{7}{130}mol.$
$⇒m_{H_2O}=\dfrac{7}{130}.18=0,97g.$
chúc bạn học tốt!