Đáp án đúng: D
0,17.
$\left\{ \begin{array}{l}{Al}\,\,{(0,14}\,{mol)}\\{F}{{{e}}_{{3}}}{{{O}}_{{4}}}\,{(x}\,{mol)}\\{C}{{{r}}_{{2}}}{{{O}}_{{3}}}\,{(x}\,{mol)}\end{array} \right.\xrightarrow{{{{t}}^{{o}}}}\left\{ \begin{array}{l}{Al}\,{(0,06}\,{mol)}\\{A}{{{l}}_{{2}}}{{{O}}_{{3}}}\,{=}\,\frac{{0,14}\,{-}\,{0,06}}{{2}}{=0,04}\,{mol}\Rightarrow {x=}\frac{{0,06}{.27+0,04}{.102+9,6-0,14}{.27}}{{232+152}}{=0,03}\\{9,6}\,{gam}\left\{ \begin{array}{l}{Fe,}\,{F}{{{e}}_{{3}}}{{{O}}_{{4}}}\\{Cr,}\,{C}{{{r}}_{{2}}}{{{O}}_{{3}}}\end{array} \right.\end{array} \right.$
$\begin{array}{l}\Rightarrow {{{n}}_{{HCl}}}{=}\frac{{38,92-0,14}{.27-0,03}{.(56}{.3+52}{.2)}}{{35,5}}{=0,76}\\\Rightarrow {a=}\frac{{0,76-0,03}{.7}{.2}}{{2}}{=0,17}\,{mol}\end{array}$