$n_M=\dfrac{4,8}{M_M}(mol)$
$2M+2xHCl\to 2MCl_x+xH_2$
$\to n_{HCl\rm pứ}=\dfrac{4,8x}{M_M}(mol)$
Nếu dùng $0,3$ mol $HCl$
$\to \dfrac{4,8x}{M_M}>0,3$
$\to 0,3M_M<4,8x$
$\to M_M<16x$
Nếu dùng $0,5$ mol $HCl$
$\to \dfrac{4,8x}{M_M}<0,5$
$\to 0,5M_M>4,8x$
$\to M_M>9,6x$
$\to 9,6x<M_M<16x$
$x=2\to 19,2<M_M<32$
$\to M_M=24(Mg)$
Vậy kim loại là magie