Em tham khảo nha :
\(\begin{array}{l}
a)\\
M + C{l_2} \to MC{l_2}\\
{n_M} = \dfrac{{4,8}}{{{M_M}}}mol\\
{n_{MC{l_2}}} = \dfrac{{19}}{{{M_M} + 71}}mol\\
{n_M} = {n_{MC{l_2}}}\\
\Rightarrow \dfrac{{4,8}}{{{M_M}}} = \dfrac{{19}}{{{M_M} + 71}} \Rightarrow {M_R} = 24dvC\\
\Rightarrow R:Magie(Mg)\\
b)\\
Mg + C{l_2} \to MgC{l_2}\\
{n_{Mg}} = \dfrac{{4,8}}{{24}} = 0,2mol\\
{n_{C{l_2}}} = {n_{Mg}} = 0,2mol\\
{n_{NaOH}} = 0,2 \times 1,5 = 0,3mol\\
2NaOH + C{l_2} \to NaCl + NaClO + {H_2}O\\
\dfrac{{0,3}}{2} < \dfrac{{0,2}}{1} \Rightarrow C{l_2}\text{ dư}\\
{n_{NaCl}} = \dfrac{{{n_{NaOH}}}}{2} = \dfrac{{0,3}}{2} = 0,15mol\\
{n_{NaClO}} = \dfrac{{{n_{NaOH}}}}{2} = \dfrac{{0,3}}{2} = 0,15mol\\
{C_{{M_{NaCl}}}} = \dfrac{{0,15}}{{0,2}} = 0,75M\\
{C_{{M_{NaClO}}}} = \dfrac{{0,15}}{{0,2}} = 0,75M
\end{array}\)
