Đáp án:
Zn + 2\(H_2SO4\rightarrow ZnSO_4+SO_2+2H_2O\)
x ------------------> x
\(Cu+2H_2SO_4\rightarrow CuSO_4+SO_2+2H_2O\)
y ------------------> y
Có : \(\left\{{}\begin{matrix}65x+64y=45\\x+y=\dfrac{15,68}{22,4}\end{matrix}\right.\) => \(\left\{{}\begin{matrix}x=0,2\\y=0,5\end{matrix}\right.\)
=> n\(_{Zn}\)= 0,2 (mol), n\(_{Cu}\)= 0,5 (mol)
=> m\(_{Zn}\) = 0,2 . 65 = 13 (g) . %m\(_{Zn}\) = \(\dfrac{13\times100}{45}\) \(\approx28,9\)
m\(_{Cu}\)= 0,5 . 64 = 32 (g)
%m\(_{Cu}\) = 100% - 28,9% = 71,1%