a) $Fe^{}$ + $2HCl^{}$ → $FeCl_{2}$ + $H_{2}$
b) Theo pt: 1 : 2 : 1 : 1
Theo đề:
$n_{Fe}$ = $\frac{5,6}{56}$ = $0,1^{}$ $(mol)^{}$
Theo pt:
$^{n}H_{2}$ = $n_{Fe}$ = $0,1^{}$ $(mol)^{}$
$^{V}H_{2}$ = $0,1^{}$ x $22,4^{}$ = $2,24^{}$ $(l)^{}$
c) Theo pt:
$^{n}FeCl_{2}$ = $^{n}H_{2}$ = $0,1^{}$ $(mol)^{}$
$^{m}FeCl_{2}$ = $0,1^{}$ x $127^{}$ = $12,7^{}$ $(g)^{}$