Gọi `a,b` là `n_{CO};n_{CO_2}`
`\overlineM_X=(28a+44b)/(a+b)=18,8.2=37,6(g//mol)`
`=>28a+44b=37,6a+37,6b`
`=>6,4b=9,6a`
`=>a/b=2/3`
`=>a=2/3b`
`n_X=(5,6)/(22,4)=0,25(mol)`
`=>a+b=0,25`
`=>2/3b+b=0,25`
`=>b=0,15`
`=>a=2/3b=0,1`
`=>`
`n_{CO}=a=0,1(mol)`
`n_{CO_2}=b=0,15(mol)`
`=>`
`%n_{CO}=(0,1)/(0,25).100=40%`
`%n_{CO_2}=(0,15)/(0,25).100=60%`
`\text{___________________________________}`
Đáp án:
`n_{CO}=0,1(mol)`
`n_{CO_2}=0,15(mol)`
`%n_{CO}=40%`
`%n_{CO_2}=60%`