Mg + 2HCl ==> MgCl2 + H2
0,1..........0,2....................................0,1 (mol)
MgO + 2HCl ==> MgCl2 + H2O
0,1......0,2
Ta có: nH2= 2,24:22,4= 0,1 (mol)
==> mMg= 0,1x24= 2,4 (g)
==> mMgO= 6,4-2,4= 4 (g)
==> nMgO= 4:40= 0,1
==> nHCl= 0,2 + 0,2= 0,4 (mol)
==> mHCl= 0,4x36,5= 14,6 (g)
==> mddHCl = (mctx100)/C%= 73 (g)
==> VHCl= mdd/D= 73/1,2= 60,83 (ml)