Đáp án:
\(\begin{array}{l} a,\ m_{ZnCl_2}=13,6\ g.\\ b,\ V_{H_2}=2,24\ lít.\\ c,\ C_{M_{HCl}}=2\ M.\end{array}\)
Giải thích các bước giải:
\(\begin{array}{l} a,\ PTHH:Zn+2HCl\to ZnCl_2+H_2↑\\ n_{Zn}=\dfrac{6,5}{65}=0,1\ mol.\\ Theo\ pt:\ n_{ZnCl_2}=n_{Zn}=0,1\ mol.\\ \Rightarrow m_{ZnCl_2}=0,1\times 136=13,6\ g.\\ b,\ Theo\ pt:\ n_{H_2}=n_{Zn}=0,1\ mol.\\ \Rightarrow V_{H_2}=0,1\times 22,4=2,24\ lít.\\ c,\ Theo\ pt:\ n_{HCl}=2n_{Zn}=0,2\ mol.\\ \Rightarrow C_{M_{HCl}}=\dfrac{0,2}{0,1}=2\ M.\end{array}\)
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