`a.`
`Zn+2HCl->ZnCl_2+H_2↑`
`n_{Zn}=(6,5)/65=0,1(mol)`
`n_{H_2}=n_{Zn}=0,1(mol)`
`V_{H_2}=0,1.22,4=2,24(l)`
`b.`
`n_{HCl}=2n_{Zn}=0,2(mol)`
`V_{ddHCl}=(0,2)/(0,2)=1(l)`
`c.`
`V_{ddspư}=V_{ddHCl}=1(l)`
`n_{ZnCl_2}=n_{Zn}=0,1(mol)`
`C_{M_{ddspư}}=(0,1)/1=0,1(M)`
`\text{___________________________________}`
Đáp án:
`a.`
`V_{H_2}=2,24(l)`
`b.`
`V_{ddHCl}=1(l)`
`c.`
`C_{M_{ddspư}}=0,1(M)`