Đáp án:
\(\begin{array}{l}
C{M_{NaOH}} = 0,6M\\
C{M_{N{a_2}S{O_4}}} = 0,25M
\end{array}\)
Giải thích các bước giải:
\(\begin{array}{l}
a)N{a_2}O + {H_2}O \to 2NaOH\\
b)\\
{n_{N{a_2}O}} = 0,15mol\\
\to {n_{NaOH}} = 2{n_{N{a_2}O}} = 0,3mol\\
\to C{M_{NaOH}} = \dfrac{{0,3}}{{0,5}} = 0,6M
\end{array}\)
\(\begin{array}{l}
c)\\
2NaOH + C{\rm{uS}}{O_4} \to N{a_2}S{O_4} + Cu{(OH)_2}\\
{n_{N{a_2}S{O_4}}} = \dfrac{1}{2}{n_{NaOH}} = 0,15mol\\
\to C{M_{N{a_2}S{O_4}}} = \dfrac{{0,15}}{{0,5 + 0,1}} = 0,25M
\end{array}\)