Cho \(A\left( { - 2;\,\,3} \right),\,\,B\left( {\dfrac{1}{4};\,\,0} \right),\,\,C\left( {2;\,\,0} \right)\). Tọa độ tâm đường tròn nội tiếp tam giác \(ABC\) là
A.\(J\left( {\dfrac{1}{2};\,\,\dfrac{1}{2}} \right)\)
B.\(J\left( {\dfrac{1}{2};\,\,\dfrac{1}{3}} \right)\)
C.\(J\left( {\dfrac{2}{3};\,\,\dfrac{3}{2}} \right)\)
D.\(J\left( {\dfrac{1}{3};\,\,\dfrac{1}{3}} \right)\)
A.\(J\left( {\dfrac{1}{2};\,\,\dfrac{1}{2}} \right)\)
B.\(J\left( {\dfrac{1}{2};\,\,\dfrac{1}{3}} \right)\)
C.\(J\left( {\dfrac{2}{3};\,\,\dfrac{3}{2}} \right)\)
D.\(J\left( {\dfrac{1}{3};\,\,\dfrac{1}{3}} \right)\)
Loga
Hóa Học lớp 12
